(4x)^2+15=10x-5

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Solution for (4x)^2+15=10x-5 equation:



(4x)^2+15=10x-5
We move all terms to the left:
(4x)^2+15-(10x-5)=0
We get rid of parentheses
4x^2-10x+5+15=0
We add all the numbers together, and all the variables
4x^2-10x+20=0
a = 4; b = -10; c = +20;
Δ = b2-4ac
Δ = -102-4·4·20
Δ = -220
Delta is less than zero, so there is no solution for the equation

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